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1
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2
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- Consider the following reaction:
- CO(g) + H2O(g) CO2(g) + H2(g)
- Kp = 0.0611 at 1000 K
- A reaction mixture initially contains partial pressures of CO and H2O
equal to 1.77 atm. The mixture is
allowed to equilibrate at 1000 K.
What are the equilibrium partial pressures of CO2, H2,
CO, and H2O?
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3
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- For the following reaction, Kc = 255 at 1000 K:
- CO(g) + Cl2(g) COCl2(g)
- A reaction mixture initially contains a CO concentration of 0.1500 M and
a Cl2 concentration of 0.175 M. The mixture is then allowed to
equilibrate at 1000 K. What are
the equilibrium concentrations of CO, Cl2, and COCl2?
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4
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- Kp = 0.11 at 25°C for the decomposition of ammonium hydrogen
sulfide:
- NH4HS(s) NH3(g) +
H2S(g)
- A sample of NH4HS is placed in an evacuated flask and allowed
to equilibrate at 25°C. What are
the equilibrium partial pressures of NH3 and H2S?
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5
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- Kc = 2.99 × 10-7 at 227°C for the reaction:
- SO2Cl2(g)
SO2(g) + Cl2(g)
- If a reaction mixture initially containing 0.175 M SO2Cl2
is allowed to equilibrate at 227°C, what is the equilibrium partial
pressure of Cl2?
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6
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- The reaction quotient, Q, is defined in a similar fashion as the
equilibrium constant.
- For a reaction:
- aA + bB ¾® cC + dD
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7
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- The pressures or concentrations in the reaction quotient are at any
point in the reaction.
- Pure solids, liquids, and solvents do not appear in reaction quotients.
- Usually, the initial pressures or concentrations are used to calculate
the value of the reaction quotient.
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8
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- The value of the reaction quotient is compared to the value of K to
determine which direction the reaction must go to reach equilibrium.
- If Q < K, reaction goes to equilibrium by moving in the forward
direction, making products.
- If Q > K, reaction goes to equilibrium by moving in the reverse
direction, making reactants.
- If Q = K, reaction is already at equilibrium.
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9
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10
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- At a particular temperature, Kc = 2.7 for the reaction:
- CO(g) + H2O(g) CO2(g) + H2(g)
- A reaction mixture contains the following concentrations: [CO] = 0.065 M; [H2O] =
0.28 M; [CO2] = 0.31 M; [H2] = 0.22 M. In which direction must the reaction
proceed to reach equilibrium?
What are the equilibrium concentrations?
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11
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- If a reaction at equilibrium is disturbed by a change in: the concentration or pressure of one
of the species in the reaction; pressure; or pressure, the reaction will
respond in such a way to partially counteract the change.
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12
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- N2(g) + 3 H2(g) 2 NH3(g)
- Suppose the reaction above is at equilibrium. Therefore, Q = K.
- Add some hydrogen gas to the mixture.
Initially, the partial pressure of H2 increases and Q
< K.
- Since Q < K, reaction moves towards products, increasing the partial
pressure of NH3, decreasing the partial pressure of N2,
and partially counteracting the increase in the partial pressure of H2.
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13
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14
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- N2(g) + 3 H2(g) 2 NH3(g)
- Reaction is initially in equilibrium, Q = K.
- Remove some nitrogen gas.
Initially, the partial pressure of N2 decreases. This will increase the value of Q.
- Q > K. The reaction moves in
the reverse direction towards reactants.
This will increase the partial pressure of H2,
decrease the partial pressure of NH3, and partially replace
the N2 that was removed.
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15
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- Pressure and/or volume changes affect gaseous species mostly. Liquids and solids are generally
unaffected by pressure changes.
- For a gas:
- Pressure is proportional to number of moles.
- Volume is inversely proportional to pressure. (Volume increase has the same effect
as a pressure decrease.)
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16
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- N2(g) + 3 H2(g) 2 NH3(g)
- An increase in pressure favors the side of the reaction with the fewer
number of moles of gas.
- A decrease in pressure favors the side of the reaction with the greater
number of moles of gas.
- For reactions with equal number of moles of gas on both sides, or for
reactions with no gaseous reactants or products, pressure has no effect.
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17
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- So far, the changes discussed so far will change the value of Q for the
reaction. The value of K does not
change.
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18
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- In order to know how temperature affects an equilibrium mixture, you
have to be given the DH for
the reaction.
- N2(g) + 3 H2(g) 2 NH3(g) DH = –91.8 kJ
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19
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- Addition of a species that does not appear in the equilibrium
expression.
- Solid, liquid, or solvent
- A species that does not appear in the reaction at all.
- Catalysts have no effect on the composition at equilibrium!!
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20
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- Consider the following reaction at equilibrium for which DH
= 16.3 kJ:
- NO(g) + Br2(g) NOBr2(g)
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