Chapter 2 Suggested Homework Answers

 

Problems 8, 10, 16, 20, 22, 24, 30, 36, 42, 44, 48, 50, 54, 56, 60, 64, 66, 68

 

8. (a) If 6.500 g of hydrogen sulfide contains 0.384 g of hydrogen, then the remaining mass must be the mass of sulfur:

Mass of sulfur = 6.500 g – 0.384 g = 6.116 g

(b) This experiment demonstrates the law of conservation of mass.

(c) In Dalton's atomic theory, atoms cannot be created nor destroyed in chemical reactions. Since atoms cannot be changed, the total mass in a chemical reaction must remain the same.

 

10.  (a) According the the law of multiple proportions, if two elements, such as iodine and fluorine, combine to form more than one compound, the masses of fluorine that combines with one gram of iodine are in the ratio of small whole numbers. In compound 1, the mass of fluorine per gram of iodine is:

For compound 2, the mass of fluorine per gram of iodine is:

For compound 3, the mass of fluorine per gram of iodine is:

To find the smallest whole number ratio between these quotients, divide each quotient by the smallest quotient in the list then multiply each number by a factor which converts all the quotients to whole numbers:

(b) According to Dalton's atomic theory, a compound forms when atoms of more than one element combine in a particular ratio. Different compounds between the same two elements will have different relative amounts of each type of atom. However, since the basic building blocks are atoms, the mass of fluorine that combines with a fixed amount of iodine will be some whole number multiple of the mass of a fluorine atom.

 

16.  (a) First divide the diameter by two to obtain the radius:

To perform the conversions, the following conversion factors were used: 1 Å = 10-10 m; 100 cm = 1 m

Therefore, the radius of a tin atom is 1.4 × 10-10 m or 1.4 Å.

(b)  Convert the diameter of a Sn atom into mm and divide it into the distance of 6.0 mm. Conversion factor: 1 mm = 10-6 m:

(c)   Calculate the volume of a Sn atom using its radius (in units of meters) and the formula for the volume of a sphere:

20 (a)  Elements are identified by their atomic number.  The atomic number in the chemical symbol notation is the subscripted number in front of the chemical symbol.  Therefore, are isotopes of the same element. 

(b)  The identity of these two isotopes is the element with an atomic number of 16.  Looking at the periodic table, this element has a chemical symbol of S, which stands for sulfur.

 

22.  (a)  Phosphorus-32 has 15 protons because the atomic number of P is 15.  It has 17 neutrons (32 – 15 = 17).

(b)  Chromium-51 has 24 protons because the atomic number of Cr is 24.  It has 27 neutrons (51 – 24 = 27).

(c)  Cobalt-60 has 27 protons because the atomic number of Co is 27.  It has 33 neutrons (60 – 27 = 33).

(d)  Technetium-99 has 43 protons because the atomic number of Tc is 43.  It has 56 neutrons (99 – 43 = 56).

(e)  Iodine-131 has 53 protons because the atomic number of I is 53.  It has 78 neutrons (131 – 53 = 78).

(f)  Thallium-201 has 81 protons because the atomic number of Tl is 81.  It has 120 neutrons (201 – 81 = 120).

 

24.   The filled-in gaps are italicized.  The atomic number is equal to the number of protons.  The mass number (mass no.) is equal to the number of protons plus the number of neutrons.  For atoms, the number of electrons is equal to the number of protons.  The symbolic notation has the mass number superscripted in front of the chemical symbol.

Symbol

121Sb

103Rh

88Sr

127Te

239Pu

Protons

51

45

38

52

94

Neutrons

70(=121-51)

58

50

75(=127–52)

145(=239–94)

Electrons

51

45

38

52

94

Mass no.

121

103(=45+58)

88(=50+38)

127

239

 

26.  The atomic weight is the weighted average of the four naturally occurring isotopes of lead:

36.  There is a stepwise line starting to the left of the element B in the periodic table and ending up between the elements Bi and Po in the periodic table.  Elements that lie to the left and/or below this stepwise line are metals.  Elements that lie to the right and/or above this stepwise line are nonmetals.  Elements that border the stepwise line are called metalloids with the exception of Al which is a metal.

(a)  Na, sodium,  is a metal.

(b)  Ti, titanium, is a metal.

(c)  Ga, gallium, is a metal.

(d)  U, uranium, is a metal.

(e)  Pd, palladium, is a metal.

(f)  Se, selenium, is a metalloid.

(g)  Kr, krypton, is a nonmetal.

 

42.  (a)  A molecule of benzene has six carbon atoms and six hydrogen atoms.  Its molecular formula is C6H6.  Divide both coefficients by “6” to obtain the empirical formula, CH.

(b)  A molecule of silicon tetrachloride has one silicon atom and four chlorine atoms.  Its molecular formula is SiCl4.  This is already the lowest whole number ratio so the empirical formula is the same as the molecular formula.

(c)  Diborane has two boron atoms and six hydrogen atoms.  Its molecular formula is B2H6.  Divide both coefficients by “2” to obtain the empirical formula, BH3.

(d)  Glucose has 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.  Its molecular formula is C6H12O6.  Divide all coefficients by “6” to obtain the empirical formula, CH2O.

 

44.  (a)  There are 4 carbon atoms in C2H5COOCH3.

(b)  There are 6 oxygen atoms in Ca(ClO3)2.  (6 = 3×2)

(c)  There are 9 hydrogen atoms in (NH4)2HPO4.  (9=4×2+1)

48.  The filled-in gaps are italicized.  The atomic number is equal to the number of protons.  The mass number (mass no.) is equal to the number of protons plus the number of neutrons.  For ions, the number of electrons is equal to the number of protons minus the net charge (or the net charge is equal to the number of protons minus the number of electrons).  The symbolic notation has the mass number superscripted in front of the chemical symbol and the charge superscripted after the chemical symbol.

Symbol

75As3-

59Ni2+

127Te¯

197Au3+

Protons

33

28

53

79(=76+3)

Neutrons

42(=75–33)

31

74

118

Electrons

36(=33-(-3))

26

54(=53–(–1))

76

Net charge

3–

2+(=28–26)

1–

3+

 

50.  (aSr is a metal in group 2A.  The charge of its ion is +2.

(b)  Sc is a metal in the “B” groups.  There is no simple rule to predict the charge of its ion.

(c)  P is a nonmetal in group 5A.  The charge of its ion is –3 (= 5 – 8).

(d)  I is a nonmetal in group 7A.  The charge of its ion is –1 (= 7 – 8).

(e)  Se is a nonmetal in group 6A.  The charge of its ion is –2 (= 6 – 8).

 

54.  For an ionic compound, the formula will have the lowest whole number ratio between the two ions in which the charges of the ions add up to zero.

(a)  The compound formed from Cu+ and S2- is Cu2S.

(b)  The compound formed from Fe3+ and O2- is Fe2O3.

(c)  The compound formed from Hg22+ and CO32- is Hg2CO3.

(d)  The compound formed from Ca2+ and AsO43- is Ca3(AsO4)2

(e)   The compound formed from NH4+ and CO32- is (NH4)2CO3

 

56.  Compounds with only nonmetal atoms are molecular.  Compounds with a metal and a nonmetal are ionic.

(a)  PF5 is molecular.

(b)  NaI is ionic.

(c)  SCl2 is molecular.

(d)  Ca(NO3)2 is ionic.

(e)  FeCl3 is ionic.

(f)  LaP is ionic.

(g)  CoCO3 is ionic.

(h)  N2H4 is molecular.

 

60.  (a)  Li2O is lithium oxide.

(b)  NaClO is sodium hypochlorite.  ClO¯ is called the hypochlorite ion.

(c)  Sr(CN)2 is strontium cyanide.  CN¯ is called the cyanide ion.

(d)  Cr(OH)3 is called chromium(III) hydroxide.  Chromium(III) ion is Cr3+.  The charge on the chromium ion can be determined from the hydroxide ion, OH¯.  Since there are 3 hydroxide for each chromium ion, its charge must be +3 so that the charges add up to zero.

(e)  Fe2(CO3)3 is called iron(III) carbonate.  Iron(III) ion is Fe3+.  The charge on the iron ion can be determined from the carbonate ion, CO32-.  Since the charge on 3 carbonate ions can cancel out the charge on 2 iron ions, the charge on the iron ion must be +3.

(f)  Co(NO3)3 is called cobalt(III) nitrate.  Cobalt(III) ion is Co3+.  The charge on the cobalt ion can be determined from the nitrate ion, NO3¯.  Since it takes three nitrate ions to cancel out the charge on the cobalt ion, its charge must be +3.

(g)  (NH4)2SO3 is called ammonium sulfite.  The ammonium ion is NH4+.  The sulfite ion is SO32-.

(h)  NaH2PO4 is called sodium dihydrogen phosphate.  The dihydrogen phosphate ion is H2PO4¯.

(i)  KMnO4 is called potassium permanganate.  The permanganate ion is MnO4¯.

(j)  Ag2Cr2O7 is called silver dichromate.  The dichromate ion is Cr2O72-.

 

64.  (aHydrobromic acid is HBr.

(b)  Hydrosulfuric acid is H2S.

(c)  Nitrous acid is HNO2.

(d)  H2CO3 is carbonic acid.

(e)  HClO3 is chloric acid.

(f)  HC2H3O2 is acetic acid.

 

66.  (a)  N2O is called dinitrogen monoxide.

(b)  NO is nitrogen monoxide.

(c)  NO2 is nitrogen dioxide.

(d)  N2O5 is dinitrogen pentoxide.

(e)  N2O4 is dinitrogen tetroxide.

 

68.  (a)  Sodium hydrogen carbonate is NaHCO3.  (Sodium ion is Na+.  Hydrogen carbonate ion is HCO3¯)

(b)  Calcium hypochlorite is Ca(ClO)2.  (Calcium ion is Ca2+.  Hypochlorite ion is ClO¯.)

(c)  Hydrogen cyanide is HCN.

(d)  Magnesium hydroxide is Mg(OH)2.  (Magnesium ion is Mg2+.  Hydroxide ion is OH¯).

(e)  Tin(II) fluoride is SnF2.  (Tin(II) ion is Sn2+.  Fluoride ion is F¯.)

(f)  Calcium sulfide is CaS (Calcium ion is Ca2+, sulfide ion is S2-).  Sulfuric acid is H2SO4.  Hydrogen sulfide is H2S.